已知π⼀4小于4分之3π,0小于β小于π⼀4,cosα=5⼀13,sinβ=5⼀13,求sinα+β

2025-12-17 17:46:54
推荐回答(2个)
回答1:

π/4<α<3π/4
cosα=5/13
sinα=根号(1-cos^2α)=12/13

0<β<π/4
sinβ=5/13
cosβ=根号(1-sin^2β)=12/13

sin(α+β)=sinαcosβ+cosαcosβ
= 12/13 * 12/13 + 5/13 * 5/13
= 1

回答2:

π/4sina>0
sina=√(1-cos^2a)=12/13
0cosb>0
cosb=√(1-sin^2b)=12/13

sin(a+b)=sinacosb+cosasinb
=12/13*12/13+5/13*5/13
=144/169+25/169
=169/169
=1